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the sum of 3 consecutive multiples of 8 is 888. find the multiples


the sum of 3 consecutive multiples of 8 is 888. find the multiples

 

x+x+8+x+16=888

3x+24=888

3x=864

x=288

First multiple = 288

second multiple= 296

third multiple = 304

sum = 888

Let the three numbers be -

 

(n-8),(n),(n+8)

The three numbers add up to 3n as -8 and 8 cancel out.

 

3n=888

n=888/3

n=296

If n is 296,the other multiples will be 296-8

=288

and 296+8

=304

The 3 multiples are 288,296 and 304.

Assume that the three consecutive multiples are 8x, 8(x+1),8(x+2) 

then the sum of three consecutive multiples are 888

so 8x + 8(x+1)+8(x+2) =888

 

x + x+1+x+2 =111

3x= 111-3

3x=108

x=36

 

The three consecutive multiples are 288,296,304

 

let the three multiple be x, x+1,x+2.

therefore, 8 * (x)= 8x, 8*(x+1)= 8x+8, 8*(x+2)= 8x+16

=>8x+8x+8+8x+16=888

=>24x+24=888

=>24x=888 - 24

=>24x=864

=>x=36

Therefore,

x=36

x+1=37

x+2=38

The three consecutive multiples are 36, 37 and 38.

 

 

 

 


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